'68 Poster
FilmDrama

'68 (1988)

1988-01-01 · 1 Std. 39 Min. · EN
34%
Nutzerwertung
5 Stimmen
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'68 covers exactly one year (January 1st through December 31st) in the lives of Zoltan Szabo and his family, Hungarian immigrants, working hard to make a life in San Francisco in 1968. The Szabos tries to adjust to the new country, changing times and each other. The year covered was one of particular cultural change in the US and this interplays with the cultural changes occurring around Zoltan, his wife and his two college-age sons. The younger of his two sons is gay and struggling with coming out. His dad disowns him when he finally does.

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Medien

Hauptbesetzung

Vollständige Besetzung & Crew →
Eric LarsonEric LarsonPeter SzaboRobert LockeRobert LockeSandy SzaboSándor TécsySándor TécsyZoltan SzaboAnna DukaszAnna DukaszZsuzsa SzaboMiran KwunMiran KwunAlana ChanNeil YoungNeil YoungWestyShony Alex BraunShony Alex BraunTibor KardosElizabeth De CharayElizabeth De CharayNike DoukasNike DoukasBeatriceTerra VandergawTerra VandergawVera KardosJan NěmecJan NěmecDezsö HorváthAnya LemAnya LemIsadora

Schlagwörter

Lgbt

Movie DNA

Genre-AffinitätDramaDialogdichteDramaRegiepräferenz324644Schauspielpräferenz247070 · 550611 · 554173Epochenpräferenz1980LaufzeitpräferenzMittel

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Worum geht es in '68?

'68 covers exactly one year (January 1st through December 31st) in the lives of Zoltan Szabo and his family, Hungarian immigrants, working hard to make a life in San Francisco in 1968. The Szabos tries to adjust to the new country, changing times and each other. The year covered was one of particular cultural change in the US and this interplays with the cultural changes occurring around Zoltan, his wife and his two college-age sons. The younger of his two sons is gay and struggling with coming out. His dad disowns him when he finally does.

Wie lang ist '68?

'68 hat eine Laufzeit von 99 Minuten.